6w^2+7w-6=0

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Solution for 6w^2+7w-6=0 equation: 



6w^2+7w-6=0

a = 6; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·6·(-6)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{193}}{2*6}=\frac{-7-\sqrt{193}}{12}
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{193}}{2*6}=\frac{-7+\sqrt{193}}{12}
$

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